Question

Решить уравнение:
(x+2)^2=4(x+4)

Answer 1

(x+2)^2=4(x+4)
x^2+4x+4=4x+16
x^2+4x+4-4x-16=0
x^2-12=0
x12=+-корень(12)

Answer 2

$(x+2)^2=4(x+4)\x^2+4x+4=4x+4\x^2=4x+4-4x-4=0\x^2=0\x=0$

Answer 3

4(x+4)=4x+16