Question

решите систему алгебра 10 класс​

Answer 1

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Answer 2

$\pi^{x} >\pi ^{y} \ \Rightarrow \ x>y\\\\\left \{ {{13^{xy} =13^{-8} } \atop {(\frac{3}{2})^{x}*(\frac{3}{2})^{y}=(\frac{3}{2})^{-2}}} \right. \\\\\left \{ {{xy=-8} \atop {x+y=-2}} \right. \\\\\left \{ {{y=-x-2} \atop {x*(-x-2)=-8}} \right.\\\\\left \{ {{y=-x-2} \atop {-x^{2}-2x+8=0 }} \right.\\\\\left \{ {{y=-x-2} \atop {x^{2}+2x-8=0 }} \right.\\\\\left \{ {{y=-x-2} \atop {\left[\begin{array}{ccc}x_{1}=-4 \\x_{2}=2 \end{array}\right }} \right.$

$1)x_{1} =-4 \ \Rightarrow \ y_{1}=-(-4)-2=4-2=2-neyd, \ tak \ kak \ x<y\\2)x_{2} =2 \ \Rightarrow \ y_{2}=-2-2=-4\\\\Otvet:\boxed{(2 \ ; - 4)}$