Question

УМАЛЯЮ ВАС ДОРЕШАЙТЕ ПРИМЕР ПЖ
{(x-y)²-x(x-2y+3)=y²+6
{(y-3) (y+3)=y²-x=4+1

{x²-2xy+y²-x²+2xy-3x=y+6
{y²-9=y²-x-y+1

Answer 1

$\left \{ {{(x-y)^{2} -x(x-2y+3)=y^{2}+6 } \atop {(y-3)(y+3)=y^{2}-x-y+1 }} \right.\\\\\left \{ {{(x-y)^{2} -x(x-2y+3)=y^{2}+6 } \atop {y^{2}-9=y^{2}-x-y+1 }} \right.\\\\\left \{ {{(x-y)^{2} -x(x-2y+3)=y^{2}+6 } \atop {x+y=10}} \right. \\\\\left \{ {{(10-y-y)^{2} -(10-y)(10-y-2y+3)=y^{2}+6 } \atop {x=10-y}} \right.\\\\\left \{ {{(10-2y)^{2}-(10-y)(13-3y)=y^{2}+6 } \atop {x=10-y}} \right.\\\\\left \{ {{100-40y+4y^{2} -130+30y+13y-3y^{2} -y^{2}=6 } \atop {x=10-y}} \right.$

$\left \{ {{3y-30=6} \atop {x=10-y}} \right.\\\\\left \{ {{3y=36} \atop {x=10-y}} \right. \\\\\left \{ {{y=12} \atop {x=10-12=-2}} \right.\\\\Otvet:\boxed{(-2 \ ; \ 12)}$