Question

$\frac{3x+y}{2x-y} +\frac{-2y-x}{2x-y}$

Answer 1

$\frac{3x+y}{2x-y} +\frac{-2y-x}{2x-y}=\frac{3x+y-2y-x}{2x-y}=\frac{2x-y}{2x-y}=\boxed1$

Answer 2

Ответ:

$\frac{3x + y}{2x - y} + \frac{ - 2y - x}{2x - y} = \frac{3x + y - 2y - x}{2x - y} = \frac{2x - y}{2x - y} = 1$