Question

Решите системное уравнение, пожалуйста​
{5(x-3y)-26=2x+1
{3(x-6y)+4=9y+19​

Answer 1

Ответ:

{5(x-3y) -26=2x+1     →    {5x - 15y -2x = 1 + 26   →   3x - 15y = 27 | : (-3)

{3(x-6y) +4=9y+19     →     {3 -18y - 9y = 19 - 4  →     3x -27y = 15 | : 3

{-x +5y = - 9         →     x = 5y + 9

{ x - 9y = 5      

 - 4y = - 4

       y = 1

x = 5 * 1 + 9 = 14

(14; 1)

Answer 2

$\left \{ {{5(x-3y)-26=2x+1} \atop {3(x-6y)+4=9y+19}} \right.\\\\\left \{ {{5x-15y-26=2x+1} \atop {3x-18y+4=9y+19}} \right.\\\\\left \{ {{5x-2x-15y=1+26} \atop {3x-18y-9y=19-4}} \right.\\\\\left \{ {{3x-15y=27} \atop {3x-27y=15}|*(-1)} \right.\\\\+\left \{ {{3x-15y=27} \atop {-3x+27y=-15}} \right.\\--------\\12y=12\\\\y=1\\\\3x=27+15y=27+15*1=42\\\\x=42:3=14\\\\Otvet:\boxed{(14 \ ; \ 1)}$