Question

Решите уравнение пожалуйста​

Answer 1

$\frac{3(x-11)}{4} =\frac{3(x+1)}{5}-\frac{2(2x-5)}{11}\\\\\frac{3(x-11)}{4}*220 =\frac{3(x+1)}{5}*220-\frac{2(2x-5)}{11}*220\\\\3*55*(x-11)=3*44*(x+1)-2*20*(2x-5)\\\\165(x-11)=132(x+1)-40(2x-5)\\\\165x-1815=132x+132-80x+200\\\\165x-132x+80x=132+200+1815\\\\113x=2147\\\\\boxed{x=19}$

Answer 2

Ответ:

$\frac{3(x - 11)}{4} = \frac{3(x + 1)}{5} - \frac{2(2x - 5)}{11} \\ \\ \frac{3x - 33}{4} = \frac{3x + 3}{5} - \frac{4x - 10}{11} \\ \\ 55(3x - 33) = 44(3x + 3) - 20(4x - 10) \\ \\ 165x - 1815 = 132x + 132 - 80x + 200 \\ \\ 165x - 1815 = 52x + 332 \\ \\ 165x - 52x = 332 + 1815 \\ \\ 113x = 2147 \\ \\ \\ x = 19$