Question

Скоротіть дріб х²+2х-3/х²-2х+1

Answer 1

Ответ:

$\dfrac{x^2+2x-3}{x^2-2x+1}=\dfrac{(x+3)(x-1)}{(x-1)^2}=\dfrac{x+3}{x-1}\\\\\\\star \ \ \ x^2+2x-3=0\ \ ,\ \ x_1=-3\ ,\ x_2=1\ \ (teorema\ Vieta)\ \ \Rightarrow \\\\x^2-2x+1=(x+3)(x-1)\ \ \star$

Answer 2

$\frac{ {x}^{2} + 2x - 3 }{ {x}^{2} - 2x + 1 } = \frac{(x + 3)(x - 1)}{(x - 1 {)}^{2} } = \frac{x + 3}{x - 1}$