Question

Сюка Помоғите
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Answer 1

Ответ:   №4 .

$\dfrac{6a^2b-6a^2}{b+2}\, :\, \dfrac{12a^3}{5b+10}+\dfrac{5}{2a}=\dfrac{6a^2(b-1)}{b+2}\cdot \dfrac{5(b+2)}{12a^3}+\dfrac{5}{2a}=\\\\\\=\dfrac{5(b-1)}{2a}+\dfrac{5}{2a}=\dfrac{5(b-1)+5}{2a}=\dfrac{5b}{2a}=\dfrac{2,5b}{a}$