Question

70 баллов, ответ не по теме бан

Answer 1

Ответ:

1.

$y' = - 5 {x}^{ - 6} - 4 \times 5 {x}^{4} + 2 \times 3 {x}^{2} - 0 = \\ = - \frac{5}{ {x}^{6} } - 20 {x}^{4} + 6 {x}^{2}$

2.

$y '= 3 \times 2x - 6 {x}^{ - 7} + 0 - 4 {x}^{3} = \\ = 6x - \frac{6}{ {x}^{7} } - 4 {x}^{3}$

3.

$y' = 2 \times ( - 0.5) {x}^{ - 1.5} + 3 {x}^{2} - 11 \times 4 {x}^{3} = \\ = - \frac{1}{x \sqrt{x} } + 3 {x}^{2} - 44 {x}^{3}$

4.

$y' = 3 \times 5 {x}^{4} - ( - 4) {x}^{ - 5} - 9 \times 6 {x}^{5} - 0 = \\ = 15 {x}^{4} + \frac{4}{ {x}^{5} } - 54 {x}^{5}$

5.

$y '= - 5 {x}^{ - 6} - 9 \times 3 {x}^{2} - 2x + 117 - 5 \times ( - 4) {x}^{ - 5} = \\ = - \frac{5}{ {x}^{6} } - 27 {x}^{2} - 2x + 117 + \frac{20}{ {x}^{5} }$

6.

$y '= 0.5 \times 2x - 4 \times ( - 4) {x}^{ - 5} + 0.3 \times 10 {x}^{9} + 1 = \\ = x + \frac{16}{x {}^{5} } + 3 {x}^{9} + 1$

7.

$y '= 0.25 \times 4 {x}^{3} + 2 \times 0.5 {x}^{ - 0.5} - 0 = 2 {x}^{3} + \frac{1}{ \sqrt{x} }$

8.

$y '= 6 {x}^{5} + 5 {x}^{4} - 4 {x}^{3} + 3 {x}^{2} - 2x + 13$

9.

$y' = 64 {x}^{7} - 49 {x}^{6} + 36 {x}^{5} - 12 {x}^{2} + 119$

10.

$y' = - 2 {x}^{ - 3} - ( - 7) {x}^{ - 8} - 12 {x}^{3} + 22 {x}^{10} = \\ = - \frac{2}{ {x}^{3} } + \frac{7}{ {x}^{8} } - 12 {x}^{3} + 22 {x}^{10}$