Question

Прошу срочно Алгебра 8 класс!!!!! ​

Answer 1

$x^{2} +2x\sqrt{2} +4=(\sqrt{2}+1)^{2} +2\sqrt{2}*(\sqrt{2}+1)+4=\\\\=2+2\sqrt{2} +1+4+2\sqrt{2} +4=\boxed{4\sqrt{2}+11}$