Question

решите уравнения.
1) y^2-4y=0
2)2x-3x^2=0

Answer 1

№1

$y^2 - 4y = 0\\y(y-4) = 0\\y = 0; y = 4$

№2

$2x - 3x^2 = 0\\x(2 - 3x) = 0\\x = 0; x = \frac{2}{3}$