Question

даю 49 б!!!!!

задание на картинке! ​

Answer 1

Ответ:

$a)\ \ \dfrac{2}{5y}+\dfrac{1}{y^2}=\dfrac{2y+5}{5y^2}\\\\\\b)\ \ \dfrac{4}{4-x}+\dfrac{x}{x^2-16}=\dfrac{4}{4-x}-\dfrac{x}{(4-x)(4+x)}=\dfrac{16+4x-x}{(4-x)(4+x)}=\dfrac{16+3x}{16-x^2}$

$c)\ \ \dfrac{5a}{27c}\cdot \dfrac{18c^2}{30a^4}=\dfrac{5a\cdot (2c\cdot 9c)}{(9c\cdot 3)\cdot (5a\cdot 6a^3)}=\dfrac{2c}{3\cdot 6a^3}=\dfrac{c}{9a^3}\\\\\\\\d)\ \ \dfrac{x^2-ax}{b^2+by}\, :\, \dfrac{8x-8a}{3y+3b}=\dfrac{x\, (x-a)}{b\, (b+y)}\cdot \dfrac{3\, (y+b)}{8\, (x-a)}=\dfrac{3x}{8b}$