Question

(1/5)^(х-1)+ (1/5)^(х+ 1) ≤26​

Answer 1

Смотрите решение. на фото :

Answer 2

Ответ:

[-1;+∞)

Пошаговое объяснение:

$(\frac{1}{5})^{x-1}+(\frac{1}{5})^{x+1}\leq26\\\\(\frac{1}{5})^{x}* (\frac{1}{5})^{-1}+(\frac{1}{5})^{x}*(\frac{1}{5})^{1}\leq26\\\\(\frac{1}{5})^{x}*5+(\frac{1}{5})^{x}*\frac{1}{5}\leq26\\\\(\frac{1}{5})^{x}(5+\frac{1}{5})\leq26\\\\(\frac{1}{5})^{x}*\frac{26}{5}\leq26|:\frac{26}{5}\\\\(\frac{1}{5})^{x}\leq5\\\\(\frac{1}{5})^{x}\leq(\frac{1}{5})^{-1}\\\\0<\frac{1}{5}<1\\\\x\geq -1$