Question

Решите 9,10 подробно

Answer 1

Ответ:

9.

$f'(x) = 2 \times 3 {x}^{2} + 4 - \frac{8}{ \cos {}^{2} (x) } = 6 {x}^{2} + 4 - \frac{8}{ \cos {}^{2} (x) }$

$f'(0) = 0 + 4 - \frac{8}{ \cos {}^{2} (0) } = 4 - 8 = - 4$

10.

$f(x) = 3 {x}^{3} \\ x_0 = - 1$

$f(x) = f(x_0) + f(x_0)(x - x_0)$

$f( - 1) = - 3$

$f'(x) = 9 {x}^{2}$

$f'( - 1) = 9$

$f(x) = - 3 + 9(x + 1) = - 3 + 9x + 9 = \\ = 9x + 6$

уравнение касательной