Question

Sin(180+30)-cos(90-45)
Tg(90-60) +ctg(270+45)
Sin(360-45) +ctg(180+60)
Sin(3п/2+a) -cos(2п-а) +ctg(п-п/4)
Tg(3п/2+п/6) -cos(2п-п/3) +ctg(2п-п/4)
Sin(3п/2+п/6) -sin(п-п/3) -tg(2п+п/4)

Answer 1

Ответ:

Пошаговое объяснение:

Sin(180°+30°)-cos(90°-45°) = - sin30° - sin45° = - 1/2 - √2 /2 = - ( 1 +√2)/2 ;

Tg(90°-60°) +ctg(270°+45°) = ctg60° - tg45° = √3/3- 1 = ( √3 - 3 )/3 ;

Sin(360°-45°) +ctg(180°+60°) = - sin60° + ctg60° = - √3/2 + √3/3= - √3/6 ;

Sin(3п/2+a) -cos(2п-а) +ctg(п-п/4) = - cosα - cosα - ctg(π/4)= - 2cosα -1 ;

Tg(3п/2+п/6) -cos(2п-п/3) +ctg(2п-п/4) = - ctgπ/6 -cosπ/3 - ctgπ/4 =

= - √3 - 1/2 - 1  = - √3 - 3/2 = - √3 - 1,5 ;

Sin(3п/2+п/6) -sin(п-п/3) -tg(2п+п/4) = - cosπ/6 - sinπ/3 - tgп/4 =

= - √3/2 - √3/2 - 1  = - √3 - 1 .