Question

Помогите пожалуйста!!!​

Answer 1

Ответ:

С)

Объяснение:

tg²(5*30° - 0.25*60°)=1

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Answer 2

Ответ:

$tg^2\Big(5arctg\dfrac{\sqrt3}{3}-0,25arcsin\dfrac{\sqrt3}{2}\Big)=tg^2\Big(5\cdot \dfrac{\pi}{6}-\dfrac{1}{4}\cdot \dfrac{\pi}{3}\Big)=\\\\\\=tg^2\Big(\dfrac{5\pi }{6}-\dfrac{\pi}{12}\Big)=tg^2\dfrac{9\pi}{12}=tg^2\dfrac{3\pi}{4}=tg^2\Big(\pi -\dfrac{\pi}{4}\Big)=tg^2\dfrac{\pi}{4}=1^2=1$