Question

пожалуйста помогите
даю 27 баллов )))

Answer 1

$(x^{2}+6x)^{2}+8(x^{2}+6x)=9\\\\x^{2} +6x=m\\\\m^{2} +8m-9=0\\\\m_{1}=-9\\\\m_{2} =1-teorema \ Vieta\\\\1)x^{2}+6x=-9\\\\x^{2}+6x+9=0\\\\(x+3)^{2} =0\\\\x+3=0\\\\x_{1}=-3\\\\2)x^{2} +6x=1\\\\x^{2} +6x-1=0\\\\D=6^{2} -4\cdot(-1)=36+4=40=(2\sqrt{10})^{2}\\\\x_{2} =\frac{-6-2\sqrt{10} }{2}=-3-\sqrt{10}\\\\x_{3}=\frac{-6+2\sqrt{10} }{2}=-3+\sqrt{10} \\\\Otvet:\boxed{-3 \ ; \ -3-\sqrt{10} \ ; \ \sqrt{10}-3}$