Question

Помогите пожалуйста по математике, 9 класс

Answer 1

$\dfrac{x^{2}+5x+6 }{x^{2}-9 } +\dfrac{4x-5}{x-3}=1 \\\\\dfrac{x^{2}+5x+6 }{(x-3)(x+3) } +\dfrac{4x-5}{x-3}-1=0\\\\\dfrac{x^{2}+5x+6+(4x-5)(x+3)-(x^{2}-9) }{8x-3)(x+3)}=0\\\\\dfrac{x^{2}+5x+6+4x^{2}+12x-5x-15-x^{2}+9}{(x-3)(x+3)}=0\\\\\dfrac{4x^{2}+12x }{(x-3)(x+3)} =0\\\\\left \{ {{4x^{2}+12x=0 } \atop {x\neq-3 \ ; \ x\neq3 }} \right.\\\\\left \{ {{x^{2}+3x=0 } \atop {x\neq-3 \ ; \ x\neq3 }} \right.\\\\\left \{ {{x(x+3)=0 } \atop {x\neq-3 \ ; \ x\neq3 }} \right.\\\\x_{1}=0$

$x_{2}=-3-neyd\\\\Otvet:\boxed0$