Question

Найти область определения функции y=arccos(x+2)

Answer 1

$y=arcCos(x+2)\\\\-1\leq x+2\leq 1\\\\-1-2\leq x+2-2\leq1-2\\\\-3\leq x\leq-1 \\\\Otvet:\boxed{[-3 \ ; \ -1]}$