Question

35 баллов даю! Лёгкий вопрос! Помогите прошу!

Answer 1

Ответ:

$\frac{ {x}^{2} - 15x + 36}{ {x}^{2} - 7x + 12 } \\ \\ {x}^{2} - 15x + 36 = 0 \\ D = 225 - 144 = 81 \\ x_1 = \frac{15 + 9}{2} = \frac{24}{2} = 12 \\ x_2 = 3 \\ \\ {x}^{2} - 7x + 12 = 0 \\ D = 49 - 48 = 1 \\ x_1 = \frac{7 + 1}{2} = 4 \\ x_2 = 3 \\ \\ \frac{ {x}^{2} - 15x + 36}{ {x}^{2} - 7x + 12 } = \frac{(x - 12)(x - 3)}{(x - 4)(x - 3)} = \\ = \frac{x - 12}{x - 4}$

Ответ: D