Question

Вычислить: 24 / (sin(49)^2 + cos(131)^2)

Answer 1

$\dfrac{24}{Sin^{2}49^\circ+Cos^{2}131^\circ}=\dfrac{24}{Sin^{2}49^\circ+Cos^{2}(180^\circ-49^\circ) } =\dfrac{24}{\underbrace{Sin^{2}49^\circ+Cos^{2}49^\circ}_{1} }=\\\\=\frac{24}{1} =\boxed{24}$