Question

y=x²-1/x+1 -5≤x≤5 срочно!!!!!​

Answer 1

Ответ:

$y=\dfrac{x^2-1}{x+1}=\dfrac{(x-1)(x+1)}{x+1}=x-1\ \ ,\ \ \ x\ne -1\\\\\\-5\leq x\leq 5\ \ \Rightarrow \ \ \ -6\leq (x-1)\leq 4\ ,\ x\ne -1\ \ \Rightarrow \\\\y\in [-6\ ;-2\ )\cup (-2\ ;\ 4\ ]$