Question

(m^3+8)/(m^2-2m+4)-m^0.5 при m=25

Answer 1

Ответ:

$22$

Объяснение:

$\dfrac{m^{3}+8}{m^{2}-2m+4}-m^{0,5}=\dfrac{(m+2)(m^{2}-2m+4)}{(m^{2}-2m+4)}-m^{\tfrac{1}{2}}=m+2-\sqrt{m} \ ;$

$m=25: \ 25+2-\sqrt{25}=27-5=22;$

Answer 2

$\dfrac{m^{3}+8 }{m^{2} -2m+4}-m^{0,5}=\dfrac{(m+2)(m^{2}-2m+4)}{m^{2} -2m+4}-m^{0,5} =m+2-\sqrt{m}\\\\m=25 \ \Rightarrow \ 25+2-\sqrt{25}=27-5=\boxed{22}$