Question

HELP!ПОЖАЛУЙСТА 35 баллов​

Answer 1

3)

$\displaystyle \int\limits {\frac{2}{cos^2(x)}-\frac{2}{sin^2(x)} } \, dx = 2\int\limits {\frac{1}{cos^2(x)}}\, dx -2\int\limits {\frac{1}{sin^2(x)}}\, dx =\\\\\\= 2tg(x) - 2ctg(x) + C$

4)

$\displaystyle \int\limits^0_{-1} {8x^2+2x-1} \, dx = \frac{8x^3}{3}+x^2-x~~~~ \bigg | \limits^0_{-1} =\\\\\\= (\frac{8*0^3}{3}+0^2-0)-(\frac{8*(-1)^3}{3}+(-1)^2+1)=\frac{8}{3} -2 = \frac{2}{3}$