Question

Помогите решить
$5x^{2} -7\frac{1}{6} x+2 \frac{1}{2}=0$

Answer 1

5х²-7⅙х+2½=0

30х²-43х+15=0

D=(-43)²-4*10*15=1849-1800=49

x₁=(43-√49)/60; x₁=3/5

х₂=(43+√49)/60; х₂=5/6

Answer 2

$5x^{2}-7\dfrac{1}{6} x+2\dfrac{1}{2}=0\\\\5x^{2} -\dfrac{43}{6} x+\dfrac{5}{2}=0\\\\5x^{2}\cdot6 -\dfrac{43}{6} x\cdot 6+\dfrac{5}{2}\cdot 6=0\\\\30x^{2} -43x+15=0\\\\D=(-43)^{2} -4\cdot 30\cdot 15=1849-1800=49=7^{2}\\\\x_{1}=\dfrac{43-7}{60} =\dfrac{36}{60}=0,6\\\\x_{2}=\dfrac{43+7}{60} =\dfrac{50}{60}=\dfrac{5}{6}\\\\Otvet:\boxed{0,6 \ ; \ \dfrac{5}{6}}$