Question

2(2x−25)2−10(2x−25)+12=0

x1 =
x2 =

Answer 1

2(2х-25)²-10(2х-25)+12=0

2(4х²-100х+625)-20х+250+12=0

8х²-200х+1250-20х+250+12=0

8х²-220х+1512=0 |÷2

х=(-(-55)±√(-55)²-4*2*378))/(2*2)

х=(55±√(3025-3024))/4

х=(55±√1)/4→х=(55±1)/4

х¹=(55+1)/4=56/4=14

х²=(55-1)/2=54/4=27/2=13½=13,5

Ответ : 13,5 ; 14.