Question

Срочно!!! 13 Балов!!!​

Answer 1

$\dfrac{8}{\sqrt6+\sqrt2}=\dfrac{8(\sqrt6-\sqrt2)}{(\sqrt6+\sqrt2)(\sqrt6-\sqrt2)}=\dfrac{8\sqrt6-8\sqrt2}{(\sqrt6)^2-(\sqrt2)^2}=\dfrac{8\sqrt6-8\sqrt2}{6-2}$