Question

Математика Математика ​

Answer 1

Объяснение:

1) $\displaystyle y=cos(x)$

$\displaystyle y'=-sin(x)$

$\displaystyle y''=-cos(x)$

2) $\displaystyle y=2x^{2} +4x-2$

$\displaystyle y'=2*2x+4=4x+4$

$\displaystyle y''=4$

3) $\displaystyle y=3x(x-1)=3x^{2} -3x$

$\displaystyle y'=3*2x-3=6x-3$

$\displaystyle y''=6$

Теория:

P.S. c - число

$(x)'=1$

$\displaystyle (cx)'=c$

$(c)'=0$

$\displaystyle (cos(x))'=-sin(x)$

$\displaystyle (sin(x))'=cos(x)$

$\displaystyle (x^{c})'=c*x^{c-1}$