Question

Очень срочно нужно решить

Answer 1

$(9x-3x^{3} +7x^{6} +1)/(1+x^{2} +x^{3} )=\frac{9x-3x^{3} +7x^{6}+1 }{1+x^{2} +x^{3} } = \frac{7x^{6} -3x^{3} +9x+1 }{x^{1} +x^{2}+1 }$

$-4x^{3} -8x^{2} -2x+6/(x+2)=-4x^{3} -8x^{2} -2x+\frac{6}{x+2} = \frac{-4x^{3}*(x-2)-8x^{2} *(x-2)-2x*(x-2)+6 }{x+2} = \frac{-4x^{4}-8x^{3} -8x^{3}-16x^{2} -2x^{2} -4x+6 }{x+2} = \frac{-4x^{4}-16x^{3}-18x^{2} -4x+6 }{x+2}$

$(2x^{2} +7x^{5} -3x^{4} +1-6x)/(x^{2} -x+1) = \frac{2x^{2} +7x^{5}-3x^{4}+1-6x}{x^{2}-x+1}=\frac{7x^{5}-3x^{4}+2x^{2}-6x+1}{x^{2} -x+1}$