Question

Срочно пожалуйста срочно нужно

Answer 1

Ответ:

а

$(2 {x}^{3} \cos(x))' = (2 {x}^{3} )' \times \cos(x) + ( \cos(x))' \times 2 {x}^{3} = \\ = 6 {x}^{2} \cos(x) - \sin(x) \times 2 {x}^{3} = 2 {x}^{2} (3 \cos(x) - x\sin(x) )$

б

$( \sin {}^{2} (x) - ctgx) '= 2 \sin(x) \times ( \sin(x)) '- ( - \frac{1}{ \sin {}^{2} (x) } ) = \\ = 2 \sin(x) \cos(x) + \frac{1}{ \sin {}^{2} (x) } = \sin(2x) + \frac{1}{ \sin {}^{2} (x) }$

в

$( {(1 - 2 {x}^{2} )}^{ \frac{1}{2} } )' = \frac{1}{2} {(1 - 2 {x}^{2} )}^{ - \frac{1}{2} } \times (1 - 2 {x}^{2} ) '= \\ = \frac{1}{2 \sqrt{1 - 2 {x}^{2} } } \times ( - 4x) = - \frac{2x}{ \sqrt{1 - 2 {x}^{2} } }$