Question

Решите систему уравнений
У=х+2
2х-у=10

Answer 1

Ответ: (12; 14)

Объяснение:

Метод подстановки:

$\left \{ {{y=x+2,} \atop {2x-y=10}} \right. \\ \\ \left \{ {{y=x+2,} \atop {2x-(x+2)=10}} \right. \\ \\ \left \{ {{y=x+2,} \atop {x-2=10}} \right. \\ \\ \left \{ {{y=12+2,} \atop {x=12}} \right. \\ \\ \left \{ {{y=14,} \atop {x=12}} \right.$

Answer 2

$\displaystyle\bf \left \{ {{y=x+2} \atop {2x-y=10}} \right. => +\left \{ {{y-x=2} \atop {-y+2x=10}} \right. => y-y+2x-x=12=>\\\\\\ x=12\quad ; \quad y=x+2=12+2=14\\\\\\Otvet: \boxed{x=12 \quad; \quad y=14}$