Question

Решите уравнение:
только 11111111111​

Answer 1

Ответ:

$x =2.$

Объяснение:

$1)\frac{7(x-6)}{4} = \frac{5(x+1)}{3} - 3(x+2)\\12*\frac{7(x-6)}{4} = 12*\frac{5(x+1)}{3} - 12* 3(x+2)\\21(x-6) = 20(x+1) -36(x+2)\\21x -126 = 20x + 20 -36x - 72\\21x - 20x + 36x = 20 - 72 + 126\\37x = 74\\x = 74 :37\\x = 2$

Проверка:

$\frac{7(2-6)}{4} = \frac{5(2+1)}{3} - 3(2+2)\\\frac{7*(-4)}{4} = \frac{5*3}{3} - 3*4\\\frac{-28}{4} = \frac{15}{3} - 12\\-7 = 5 - 12\\-7 = -7$

Answer 2

$\dfrac{7(x-6)}{4} =\dfrac{5(x+1)}{3} -3(x+2)\\\\\dfrac{7(x-6)}{4}\cdot12 =\dfrac{5(x+1)}{3}\cdot12 -3(x+2)\cdot12\\\\3\cdot7(x-6)=4\cdot5(x+1)-36(x+2)\\\\21(x-6)=20(x+1)-36(x+2)\\\\21x-126=20x+20-36x-72\\\\21x-126=-52-16x\\\\21x+16x=-52+126\\\\37x=74\\\\\boxed{x=2}$