Question

ПЖПЖПЖПЖ!!!!ОЧЕНЬ СРОЧНО!!!!​

Answer 1

Ответ:

1.

$1)-\frac{3}{5}+\frac{1}{4}=-\frac{12}{20}+\frac{5}{20}=-\frac{7}{20}\\2)3\frac{1}{2}+(-4\frac{2}{3})=\frac{7}{2}-\frac{14}{3}=\frac{21}{6}-\frac{28}{6}=-1\frac{1}{6} \\3)-16\frac{4}{5}+7\frac{5}{6}=-\frac{84}{5}+ \frac{47}{6}=-\frac{504}{30}+\frac{235}{30} = -8\frac{29}{30} \\4)\frac{7}{8}+(-\frac{5}{12})=\frac{21}{24}-\frac{10}{24}=\frac{11}{24} \\5)-8\frac{5}{7}+1\frac{3}{4}=-\frac{61}{7}+ \frac{7}{4}=-\frac{244}{28} +\frac{49}{28} =-6\frac{27}{28}$

$6)5\frac{3}{8}+(-3\frac{1}{12})=\frac{43}{8}-\frac{37}{12}=\frac{129}{24}-\frac{74}{24}=\frac{55}{24}$

2.

$1)-5.3+4\frac{2}{3}=-5\frac{3}{10}+4\frac{2}{3}=-\frac{159}{30}+\frac{140}{30}=-\frac{19}{40}\\2)3.05+(-2\frac{2}{3})=3\frac{1}{20} -2\frac{2}{3}=\frac{61}{20}-\frac{8}{3}=\frac{183}{60}-\frac{160}{60}=\frac{23}{60}\\3)-6.02+6\frac{1}{5}=6.02+6.2=6.02+6.20=12.22=12\frac{11}{50}\\4)8\frac{1}{6}+(-12.7)=8\frac{1}{6}-12\frac{7}{10}=\frac{49}{6}-\frac{127}{10}=\frac{490}{60}-\frac{762}{60}=-4\frac{8}{15}$$5)0.6+(-1\frac{1}{6})=\frac{3}{5}-\frac{7}{6}=\frac{18}{30}-\frac{35}{30}=-\frac{17}{30} \\6)-15.3+7\frac{2}{3}=-15\frac{3}{10}+7\frac{2}{3}=-\frac{153}{10}+\frac{23}{3}=-\frac{459}{30}+\frac{230}{30}=-7\frac{19}{30}$

Пошаговое объяснение:

Answer 2

Решение дано на фотографии