Question

Помогите!!!!!просто дроби решите за это 30 балов

Answer 1

++++++++++++++++++++++++++++++++++++++++++++++++++++++++++

Answer 2

Ответ и пошаговое объяснение:

$36.\\A)\ \dfrac{11}{27} + \dfrac{4^{/3}}{9} = \dfrac{11}{27} + \dfrac{12}{27} = \dfrac{11+12}{27} = \dfrac{23}{27};\\\\B)\ \dfrac{8^{/4}}{11} + \dfrac{5}{44} = \dfrac{32}{44} + \dfrac{5}{44} = \dfrac{32+5}{44} = \dfrac{37}{44};\\\\C)\ \dfrac{11}{25} + \dfrac{2^{/5}}{5} = \dfrac{11}{25} + \dfrac{10}{25} = \dfrac{11+10}{25} = \dfrac{21}{25};\\\\D)\ \dfrac{1^{/6}}{6} + \dfrac{13}{36} = \dfrac{6}{36} + \dfrac{13}{36} = \dfrac{6+13}{36} = \dfrac{19}{36}.$

$37.\\A)\ \dfrac{9}{28} + \dfrac{3^{/4}}{7} = \dfrac{9}{28} + \dfrac{12}{28} = \dfrac{9+12}{28} = \dfrac{21}{28};\\\\B)\ \dfrac{7^{/10}}{30} + \dfrac{11}{300} = \dfrac{70}{300} + \dfrac{11}{300} = \dfrac{70+11}{300} = \dfrac{81}{300};\\\\C)\ \dfrac{1}{40} + \dfrac{3^{/8}}{5} = \dfrac{1}{40} + \dfrac{24}{40} = \dfrac{1+24}{40} = \dfrac{25}{40} =\dfrac{5}{8} ;\\\\D)\ \dfrac{4^{/4}}{9} + \dfrac{5}{36} = \dfrac{16}{36} + \dfrac{5}{36} = \dfrac{16+5}{36} = \dfrac{21}{36} =\dfrac{7}{12} .$