Question

Решить :
2cosx=4sinx​

Answer 1

Ответ:

$x=\mathrm{arctg}~\dfrac12+\pi n,~n\in\mathbb{Z}$

Объяснение:

$2\cos x = 4\sin x\\\cos x = 2 \sin x\\\cos x = 2 \sin x~~\Big|\div \cos x,~\cos x\ne0\\\dfrac{\cos x}{\cos x}=\dfrac{2\sin x}{\cos x}\\\\1=2\mathrm{tg}~x\\\mathrm{tg}~x=\dfrac12\\x=\mathrm{arctg}~\dfrac12+\pi n,~n\in\mathbb{Z}$