Question

Помогите решить задачу!!!​

Answer 1

log(a) x / log(a) y = log(y) x

x^ log(x) y = y

log(6)(log(6)(√2 + 1)) / log(6)(√2 + 1) = log(√2 + 1) (log(6)(√2 + 1))

1/(3 - 2√2) = (3 + 2√2) /((3 - 2√2)(3 + 2√2)) = (2 + 2√2 + 1) / (9 - 8) = (√2 + 1)²

(1/(3 - 2√2))^( log(6)(log(6)(√2 + 1)) / log(6)(√2 + 1)) = (√2 + 1)^2 log(√2 + 1) (log(6)(√2 + 1)) = (√2 + 1)^ log(√2 + 1) (log(6)(√2 + 1))² = log²(6)(√2 + 1)

Answer 2

Решение задания прилагаю