Question

нужно решить уравнение
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Answer 1

$x^{2} +3x-2=0\\\\Teorema \ Vieta :\\\\x_{1} +x_{2} =-3\\\\x_{1} \cdot x_{2}=-2\\\\x_{1} ^{3} +x_{2}^{3}=(x_{1} +x_{2})(x_{1} ^{2} -x_{1}x_{2}+x_{2} ^{2})=(x_{1} +x_{2})\cdot [(x_{1} +x_{2})^{2}-3x_{1}x_{2}]=\\\\=-3\cdot [(-3)^{2} -3\cdot (-2)]=-3\cdot(9+6)=\boxed{-45}$