Question

Помогите Решить систему уравнения

Answer 1

$\left\{\begin{array}{ccc}\dfrac{3x-10}{5}-\dfrac{2x-2y}{3}=\dfrac{3x+4}{15}\\\dfrac{5x-34}{12}+\dfrac{3y+4}{2}=\dfrac{5y}{3}\end{array}\right \\\\\\\left\{\begin{array}{ccc}\dfrac{3x-10}{5}\cdot 15-\dfrac{2x-2y}{3}\cdot 15=\dfrac{3x+4}{15}\cdot 15\\\dfrac{5x-34}{12}\cdot 12+\dfrac{3y+4}{2}\cdot 12=\dfrac{5y}{3}\cdot 12\end{array}\right \\\\\\\left\{\begin{array}{ccc}3(3x-10)-5(2x-2y)=3x+4\\5x-34+6(3y+4)=4\cdot 5y\end{array}\right$

$\left\{\begin{array}{ccc}9x-30-10x+10y=3x+4\\5x-34+18y+24=20y\end{array}\right\\\\\\\left\{\begin{array}{ccc}-4x+10y=34\\5x-2y=10 \ |\cdot5\end{array}\right\\\\\\+\left\{\begin{array}{ccc}-4x+10y=34\\25x-10y=50 \ \end{array}\right\\ ----------\\21x=84\\\\x=4\\\\2y=5x-10=5\cdot 4-10=20-10=10\\\\y=5\\\\Otvet:\boxed{(4 \ ; \ 5)}$