Question

1 и 3 пункты, пожалуйста

Answer 1

Объяснение:

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Answer 2

Ответ:

$1)\ \left\{\begin{array}{l}\sqrt[3]{y}-\sqrt{x}=7\\\sqrt{x}\cdot \sqrt[3]{y}=18\end{array}\right\ \ \left\{\begin{array}{l}t=\sqrt[3]{y}\\p=\sqrt{x}\geq 0\ ,\ x\geq 0\end{array}\right\ \ \left\{\begin{array}{l}t-p=7\\p\cdot t=18\end{array}\right\\\\\\\left\{\begin{array}{l}t=p+7\\p(p+7)=18\end{array}\right\ \ \left\{\begin{array}{l}t=p+7\\p^2+7p-18=0\end{array}\right\ \ \left\{\begin{array}{l}t=p+7\\p_1=-9\ ,\ p_2=2\end{array}\right$

$\left\{\begin{array}{l}t_1=-2\ ,\ t_2=9\\p_1=-9\ ,\ p_2=2\end{array}\right\ \ \left\{\begin{array}{l}\sqrt[3]{y}=-2\ \ \ ,\ \ \ \sqrt[3]{y}=9\\\sqrt{x}=-9<0\ ,\ \sqrt{x}=2\end{array}\right\ \ \Rightarrow \ \ \left\{\begin{array}{l}\sqrt[3]{y}=9\\\sqrt{x}=2\end{array}\right\\\\\\\left\{\begin{array}{l}y=729\\x=4\end{array}\right\ \ \ \ Otvet:\ \ (\ 4\ ;729\ )\ .$

$2)\\\\\left\{\begin{array}{l}\sqrt{3x-y+3}=2\\\sqrt{x+2y+4}=4-x\end{array}\right\ \ \left\{\begin{array}{l}3x-y+3=4\\x+2y+4=16-8x+x^2\\4-x\geq 0\end{array}\right\ \ \left\{\begin{array}{l}y=3x-1\\x^2-9x+12-2y=0\\x\leq 4\end{array}\right$

$\left\{\begin{array}{l}y=3x-1\\x^2-9x+12-2(3x-1)=0\\x\leq 4\end{array}\right\ \ \left\{\begin{array}{l}y=3x-1\\x^2-15x+14=0\\x\leq 4\end{array}\right\ \ \left\{\begin{array}{l}y=3x-1\\x_1=1\ ,\ x_2=14\\x\leq 4\end{array}\right\\\\\\\left\{\begin{array}{l}x=1\\y=2\end{array}\right\ \ \ Otvet:\ \ (\ 1\ ;\ 2\ )\ .$