Question

СРОЧНО ДАЮ 23 БАЛЛА!!
С ПОДРОБНЫМ РЕШЕНИЕМ!!

Answer 1

Пояснення:

$a) \frac{2*3^{20}-5*3^{19}}{9^9}$=$\frac{2*3^{19}*3-5*3^{19}}{9^9}$=$\frac{3^{19}(6-5)}{9^9}$=$\frac{3^{19}}{3^{18}}=3$

$b) \frac{(3*2^{20}+7*2^{19})*52}{(13*8^4)^2}$=$\frac{(3*2^{19}*2+7*2^{19})*52}{(13*8^4)^2}$=$\frac{2^{19}(6+7)*52}{(13*8^4)^2}$=$\frac{2^{19}*13*52}{(13*8^4)^2}$=$\frac{2^{19}*13*52}{13^2*8^8}$=$\frac{2^{19}*13*52}{13^2*(2^3)^8}$=$\frac{52}{13*2^5} =\frac{52}{13*5} =\frac{4}{2^5} =\frac{2^2}{2^5} =\frac{1}{2^3} = 1/8$

$c)\frac{108*6^7-108*6^6}{2(6^3-36^4)}$=$\frac{108*6^6(6-1)}{216^3-36^4} =\frac{108*6^6*5}{(6^3)^3-(6^2)^4} =\frac{108*6^6*5}{6^9-6^8}$=$\frac{108*6^6*5}{6^8(6-1)} =\frac{108}{6^2} =\frac{108}{36} =3$

$d)\frac{(3^{15}+3^{13})*2^9}{(3^{14}+3^{12})*1024} =\frac{3^{13}(9+1)*2^9}{3^12(9+1)*1024} =\frac{3*2^9}{1024} =\frac{3*2^9}{1024} =(1024=2^{10})=\frac{3*2^9}{2^{10}} =3/2$

Answer 2

Решение:

а) $\frac{2*3^{20}-5*3^{19}}{9^{9}}=\frac{(2*3-5)*3^{19}}{3^{18}}=(6-5)*3^{1} = 1*3 = 3$

б) $\frac{(3*2^{20}+7*2^{19})*52}{(13*8^{4})^{2}}=\frac{(3*2+7)*2^{19}*52}{169*8^{8}}=\frac{(6+7)*2^{19}*52}{169*2^{24}}=\frac{13*52}{169*2^{5}}=\frac{52}{13*2^{5}}=\frac{4}{2^{5}}=\frac{2^{2}}{2^{5}}=\frac{1}{2^{3}}=\frac{1}{8}$

в) $\frac{108*6^{7}-108*6^{6}}{216^{3}-36^{4}}=\frac{108*6^{6}*(6-1)}{(6^{3})^{3}-(6^{2})^{4}}=\frac{108*6^{6}*5}{6^{9}-6^{8}}=\frac{108*6^{6}*5}{(6-1)*6^{8}}=\frac{108*5}{5*6^{2}}=\frac{108}{36}=3$

г) $\frac{(3^{15}+3^{13})*2^{9}}{(3^{14}+3^{12})*1024}=\frac{(3^{2}+1)*3^{13}*2^{9}}{(3^{2}+1)*3^{12}*2^{10}}=\frac{(9+1)*3}{(9+1)*2}=\frac{10*3}{10*2}=\frac{30}{20}=\frac{3}{2}=1\frac{1}{2}$

$DK954$