Question

п.ж помогите по алгебре ​

Answer 1

Ответ:

Объяснение:

$\large \boldsymbol {\sf 1)} \ \ \sf \large \boldsymbol {} \displaystyle {} 3 \frac{1}{9} : 2\frac{1}{3} -2\frac{5}{6} = \boldsymbol {\sf -1 \frac{1}{2}} \\\\\\1) \ 3\frac{1}{9} :2\frac{1}{3} =\frac{28}{9 } \cdot \frac{3}{7} =\frac{4}{3} =1\frac{1}{3} \\\\\\2) \ \ 1\frac{1}{3} -2\frac{5}{6} =1-2+\frac{1}{3}\cdot \frac{2}{2} -\frac{5}{6} =-1 +\frac{2-5 }{6} =-1 -\frac{3}{6} =\boxed{\sf -1\frac{1}{2} }$

$\large \displaystyle \sf \boldsymbol {\sf 3)} \ \ 10\frac{16}{17} :8\frac{5}{11} +1\frac{2}{3} =\boldsymbol { \sf 2\frac{49}{51}} \\\\\\1)\ \ 10 \frac{16}{17} :8\frac{5}{11} =\frac{186}{17} \cdot \frac{11}{93} = \frac{2\cdot 93\!\!\!\!/}{17} \cdot \frac{11}{93\!\!\!\! /} =\frac{2\cdot 11}{17} =\frac{22}{17 } =1 \frac{5}{17} \\\\\\2) \ \ 1\frac{2}{3} +1\frac{5}{17} =1+1+\frac{2}{3}\cdot \frac{17}{17} +\frac{5}{17 }\cdot \frac{3}{3} =2+\frac{34+15}{51} =\boxed{\sf 2\frac{49}{51} }$