Question

6x 3
------ - --------
x² - y² x-y

(6x / x² - y²) - (3 / x-y)

При
2
x = -- ----- = -(2/3)
3

y = 3/4

Answer 1

Ответ:

$\frac{3}{x+y}$, $36$

Объяснение:

$\frac{6x}{x^2-y^2}-\frac{3}{x-y}=\frac{3*2x}{(x+y)(x-y)}-\frac{3}{x-y} = \frac{3}{x-y}(\frac{2x}{x+y}-1)=\frac{3}{x-y}*\frac{2x-x-y}{x+y}=\\\frac{3}{x-y}*\frac{x-y}{x+y}=\frac{3}{x+y}$

При $x=-\frac{2}{3}$, $y=\frac{3}{4}$ $\frac{3}{-\frac{2}{3}+\frac{3}{4}}=36$