Question

9. Вычислите: 2) 17/32-5/12 ; 3) 11/28!9/14 ; 4) 35/36-41/45 ; 5) 3 21/25+ 1 2/5 ; 6) 4 13/16 - 2 3/8 ; 7) 5 5/6 - 31/48

Пожалуйста помогите!​

Answer 1

Ответ:

1)3/20+2/15=17/60

2)17/32-5/12=11/96

3)17/28+9/14=1 1/28

4)35/36-41/45=11/180

Answer 2

Пошаговое объяснение:

1).

$\frac{3(3)}{20(3)} + \frac{2(4)}{15(4)} = \frac{9}{60} = \frac{8}{60} = \frac{17}{60}$

2).

$\frac{17(3)}{32(3)} - \frac{5(8)}{12(8)} = \frac{51}{96} - \frac{40}{96} = \frac{11}{96}$

3).

$\frac{11(1)}{28(1)} + \frac{9(2)}{14(2)} = \frac{11}{28} + \frac{18}{28} = \frac{29}{28} = 1 \frac{1}{28}$

4).

$\frac{35(5)}{36(5)} - \frac{41(4)}{45(4)} = \frac{175}{180} - \frac{164}{180} = \frac{11}{180}$

5).

$3 \frac{21(1)}{25(1)} + 1 \frac{2(5)}{5(5)} = 3 \frac{21}{25} + 1 \frac{10}{25} = 4 \frac{31}{25} = 5 \frac{6}{25}$

6).

$4 \frac{13(1)}{16(1)} - 2 \frac{3(2)}{8(2)} = 4 \frac{13}{16} - 2 \frac{6}{16} = 2 \frac{7}{16}$

7).

$5 \frac{5(8)}{6(8)} - \frac{31(1)}{48(1)} = 5 \frac{40}{48} - \frac{31}{48} = 5 \frac{9}{48} = 5 \frac{3}{16}$

8).

$6 \frac{4(11)}{7(11)} - 2 \frac{37(1)}{77(1)} = 6 \frac{44}{77} - 2 \frac{37}{77} = 4 \frac{7}{77} = 4 \frac{1}{11}$