Question

x2 - 13x + 42 = 0 пжж​

Answer 1

Ответ:

6 и 7

Пошаговое объяснение:

${x}^{2} - 13x + 42 = 0 \\ a = 1 \: b = - 13 \: c = 42 \\ d = {b}^{2} - 4ac = \\ = 169 - 4 \times 42 = 169 - 168 = 1$

$x1 = \frac{ - b - \sqrt{d} }{2a} = \frac{13 - 1}{2} = \frac{12}{2} = 6$

$x2 = \frac{ - b + \sqrt{d} }{2a} = \frac{13 + 1}{2} = \frac{14}{2} = 7$