Question

Помогите с алгеброй (4)

Answer 1

Ответ:

$\left\{\begin{array}{l}4(x+1)\leq 9-2x\\2(x+5)\leq 1-x\end{array}\right\ \ \left\{\begin{array}{l}4x+4\leq 9-2x\\2x+10\leq 1-x\end{array}\right\ \ \left\{\begin{array}{l}6x\leq 5\\3x\leq -9\end{array}\right\ \ \left\{\begin{array}{l}x\leq \dfrac{5}{6}\\x\leq -3\end{array}\right\\\\\\x\in (-\infty \, ;-3\ ]$