Question

Решите нормально!!! ​

Answer 1

Ответ:

х∈(-6; 0,75]

Объяснение:

$\left \{ {{10+5x>-20} \atop {\frac{5}{11}-\frac{20}{33}x\geq 0 }} \right.\\\left \{ {{5x>-30} \atop {-\frac{20}{33}x\geq -\frac{5}{11} }} \right.$

$\left \{ {{x>-6} \atop {x\leq \frac{5*33}{11*20} }} \right.\\\left \{ {{x>-6} \atop {x\leq 0,75}} \right.$

х∈(-6; 0,75]