Question

Решить примеры с дробями ( пожалуйста с разбором действий)

Answer 1

Ответ:

Объяснение:

1)

$2\frac{3}{8}:(1\frac{2}{3} -\frac{5}{6}):0,2=\frac{19}{6}:(\frac{5}{3}-\frac{5}{6}):\frac{1}{5}=2\frac{3}{8}:\frac{5*2-5 }{6}:\frac{1}{5}=\frac{19}{6}:\frac{5}{6}:\frac{1}{5} =\\=\frac{19}{6}*\frac{6}{5}*\frac{5}{1}=\frac{19*6*5}{6*5*1}=19.$

2)

$5\frac{7}{9}*(2\frac{3}{4}-\frac{1}{2}):(1\frac{2}{5} +3\frac{7}{10})=\\\frac{52}{9}*(2,75-0,5):(1,4+3,7)=\frac{52}{9}*2,25:5,1=\frac{52}{9}*2\frac{1}{4}:\frac{51}{10} =\\=\frac{52}{9}*\frac{9}{4}*\frac{10}{51} =\frac{130}{51} =2\frac{30}{51}.$

3)

$(2\frac{5}{18}-3\frac{1}{6}+18\frac{2}{3}-11\frac{7}{9})*4,5=(\frac{41}{18}-\frac{19}{6} +\frac{56}{3} -\frac{106}{9} )*\frac{9}{2}=\\=\frac{41-19*3+56*6-106*2}{18}*\frac{9}{2}=\frac{41-57+336-212}{18} *\frac{9}{2}=\frac{208}{18}*\frac{9}{2}=52.$

4)

$\frac{17}{24}-13\frac{5}{12} +2\frac{2}{3}-\frac{5}{6}-1\frac{1}{8} =\frac{17}{24}-\frac{161}{12} +\frac{8}{3} -\frac{5}{6} -\frac{9}{8}=\frac{17-2*161+8*8-4*5-9*3}{24} =\\=\frac{17-322+64-20-27}{24}=-\frac{288}{24} =-12.$

5)

$\frac{2}{5}*(-0,5):\frac{7}{12}*2\frac{1}{3} :(-3,6)*(-27)=\frac{2}{5}*(-\frac{1}{2}):\frac{7}{12}*\frac{7}{3} :(-3\frac{3}{5})*(-27) =\\=-\frac{1}{5}*\frac{12}{7}*\frac{7}{3}:(-\frac{18}{5})*(-27 )=-\frac{4}{5}*\frac{5}{18} *\frac{27}{1} =-6.$