Question

помогите пожалуйста

Answer 1

Объяснение:

$1)\ \\a)\ 2^3*2^4=2^{3+4}=2^7=128.\\b)\ 2^6*2^2=2^{6+2}=2^8=256.\\2)\\(3^{-2}xy^{-2})^{-3}=3^6x^{-3}y^6=729\frac{y^6}{x^3} .\\3)$

функция | y=1-4x | y=3x² | y=-2/x | y=(1/2)*x³ | y=-(1/5)*x² |

график   |     5     |     4    |     2     |        1        |         3       |

$4)\\1. \ x^4-60x+900=(x^2)^2-2*x*30+3+30^2=(x^2-30)^2.\\2.\ 1000x^3-y^3=(10x)^3-y^3=(10x-y)*(100x^2+10xy+y^2).$

$5)\\1.\ (4x^3+3y)^2=16x^6+24x^3y+9y^2.\\2.\ (\frac{3}{4}a+\frac{2}{5}b)^2=\frac{9}{16} a^2+2*\frac{3}{4}a*\frac{2}{5}b+\frac{4}{25}b^2=\frac{9}{25} a^2+\frac{3}{5}ab+\frac{4}{25} b^2.$

$6)\\9x^2-(3x-2)^2=1\\9x^2-(9x^2-12x+4)=1\\9x^2-9x^2+12x-4=1\\12x=5\ |:12\\x=\frac{5}{12} .$

$7)\\1.\ 62^2-38^2=(62-38)*(62+38)=24*100=2400.\\2.\ 49*51=(50-1)*(50+1)=50^2-1^2=2500-1=2499.$

$8)\\\frac{25-4b^2}{15-6b}= \frac{5^2-(2b)^2}{3*(5-2b)} =\frac{(5-2b)*(5+2b)}{3*(5-2b)} =\frac{5+2b}{3}.$