Question

х2 степень-х-6=0 решите уравнение ​

Answer 1

${x}^{2} - x - 6 = 0$

$D = {b}^{2} - 4ac = {( - 1)}^{2} - 4 \times 1 \times ( - 6) = 1 + 24 = 25, \sqrt{D} = \sqrt{25} = 5$

$x_1 = \frac{ - b + \sqrt{D} }{2a} = \frac{1 + 5}{2} = \frac{6}{2} = 3$

$x_1 = \frac{ - b - \sqrt{D} }{2a} = \frac{1 - 5}{2} = \frac{ - 4}{2} = - 2$

Ответ: -2; 3