Question

!!! ДАЮ 25 БАЛЛОВ!!! ПОМОГИТЕ ПРОШУ!!!

Answer 1

Ответ:

$\displaystyle \frac{t}{(t+5)^2}-\frac{t}{t^2-25}=\frac{t(t-5)-t(t+5)}{(t+5)(t+5)(t-5)}=\frac{t^2-5t-t^2-5t}{(t+5)^2(t-5)}=\frac{-10t}{(t+5)^2(t-5)}\\\\\\B={(t+5)(t+5)(t-5)=(t+5)^2(t-5)$

Answer 2

Объяснение:

\begin{gathered}\displaystyle \frac{t}{(t+5)^2}-\frac{t}{t^2-25}=\frac{t(t-5)-t(t+5)}{(t+5)(t+5)(t-5)}=\frac{t^2-5t-t^2-5t}{(t+5)^2(t-5)}=\frac{-10t}{(t+5)^2(t-5)}\\\\\\B={(t+5)(t+5)(t-5)=(t+5)^2(t-5)\end{gathered}

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